Integrand size = 28, antiderivative size = 132 \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=-\frac {2 e^4 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{15 a^4 d \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}}+\frac {4 i e^2 (e \sec (c+d x))^{3/2}}{9 a d (a+i a \tan (c+d x))^3}-\frac {4 i e^4}{15 d \sqrt {e \sec (c+d x)} \left (a^4+i a^4 \tan (c+d x)\right )} \]
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Time = 0.17 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.107, Rules used = {3581, 3856, 2719} \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=-\frac {4 i e^4}{15 d \left (a^4+i a^4 \tan (c+d x)\right ) \sqrt {e \sec (c+d x)}}-\frac {2 e^4 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{15 a^4 d \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}}+\frac {4 i e^2 (e \sec (c+d x))^{3/2}}{9 a d (a+i a \tan (c+d x))^3} \]
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Rule 2719
Rule 3581
Rule 3856
Rubi steps \begin{align*} \text {integral}& = \frac {4 i e^2 (e \sec (c+d x))^{3/2}}{9 a d (a+i a \tan (c+d x))^3}-\frac {e^2 \int \frac {(e \sec (c+d x))^{3/2}}{(a+i a \tan (c+d x))^2} \, dx}{3 a^2} \\ & = \frac {4 i e^2 (e \sec (c+d x))^{3/2}}{9 a d (a+i a \tan (c+d x))^3}-\frac {4 i e^4}{15 d \sqrt {e \sec (c+d x)} \left (a^4+i a^4 \tan (c+d x)\right )}-\frac {e^4 \int \frac {1}{\sqrt {e \sec (c+d x)}} \, dx}{15 a^4} \\ & = \frac {4 i e^2 (e \sec (c+d x))^{3/2}}{9 a d (a+i a \tan (c+d x))^3}-\frac {4 i e^4}{15 d \sqrt {e \sec (c+d x)} \left (a^4+i a^4 \tan (c+d x)\right )}-\frac {e^4 \int \sqrt {\cos (c+d x)} \, dx}{15 a^4 \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}} \\ & = -\frac {2 e^4 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{15 a^4 d \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}}+\frac {4 i e^2 (e \sec (c+d x))^{3/2}}{9 a d (a+i a \tan (c+d x))^3}-\frac {4 i e^4}{15 d \sqrt {e \sec (c+d x)} \left (a^4+i a^4 \tan (c+d x)\right )} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 1.72 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.13 \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=\frac {e^3 e^{-i d x} \sec ^4(c+d x) \sqrt {e \sec (c+d x)} \left (-7-7 \cos (2 (c+d x))+6 e^{2 i (c+d x)} \sqrt {1+e^{2 i (c+d x)}} \operatorname {Hypergeometric2F1}\left (-\frac {1}{4},\frac {1}{2},\frac {3}{4},-e^{2 i (c+d x)}\right )+3 i \sin (2 (c+d x))\right ) (-i \cos (c+2 d x)+\sin (c+2 d x))}{45 a^4 d (-i+\tan (c+d x))^4} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 508 vs. \(2 (140 ) = 280\).
Time = 8.04 (sec) , antiderivative size = 509, normalized size of antiderivative = 3.86
method | result | size |
default | \(-\frac {2 i \sqrt {e \sec \left (d x +c \right )}\, \left (40 i \left (\cos ^{5}\left (d x +c \right )\right ) \sin \left (d x +c \right )+40 i \sin \left (d x +c \right ) \left (\cos ^{4}\left (d x +c \right )\right )-40 \left (\cos ^{6}\left (d x +c \right )\right )-16 i \left (\cos ^{3}\left (d x +c \right )\right ) \sin \left (d x +c \right )-40 \left (\cos ^{5}\left (d x +c \right )\right )+3 \left (\cos ^{2}\left (d x +c \right )\right ) F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}-3 \left (\cos ^{2}\left (d x +c \right )\right ) E\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}-16 i \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )+36 \left (\cos ^{4}\left (d x +c \right )\right )+6 \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \cos \left (d x +c \right )-6 \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, E\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \cos \left (d x +c \right )-3 i \cos \left (d x +c \right ) \sin \left (d x +c \right )+36 \left (\cos ^{3}\left (d x +c \right )\right )+3 F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}-3 \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, E\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\right ) e^{3}}{45 a^{4} d \left (\cos \left (d x +c \right )+1\right )}\) | \(509\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.08 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.97 \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=\frac {{\left (-6 i \, \sqrt {2} e^{\frac {7}{2}} e^{\left (5 i \, d x + 5 i \, c\right )} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, e^{\left (i \, d x + i \, c\right )}\right )\right ) + \sqrt {2} {\left (-6 i \, e^{3} e^{\left (6 i \, d x + 6 i \, c\right )} - 4 i \, e^{3} e^{\left (4 i \, d x + 4 i \, c\right )} + 7 i \, e^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + 5 i \, e^{3}\right )} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}\right )} e^{\left (-5 i \, d x - 5 i \, c\right )}}{45 \, a^{4} d} \]
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Timed out. \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=\text {Exception raised: RuntimeError} \]
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\[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=\int { \frac {\left (e \sec \left (d x + c\right )\right )^{\frac {7}{2}}}{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{4}} \,d x } \]
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Timed out. \[ \int \frac {(e \sec (c+d x))^{7/2}}{(a+i a \tan (c+d x))^4} \, dx=\int \frac {{\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{7/2}}{{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^4} \,d x \]
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